Thoughts. How does run out affect a bored hole?

Martin W

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I am Not a machinist.
Let’s say you have a 24”long boring bar on a horizontal boring mill. At the cutting tool it has 10 thou of runout. How does this affect the hole? It would still be turning in a perfect circle? Is the hole oblong?

Thanks CheersMartin
 

Litlerob1

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You'll need to be more specific when you say "runout". Do you mean Total Indicator Reading (TIR), at the tool tip, is the tool moving in the taper? Or TIR at the holder on rotation in the taper?

Mostly your problem would end up being Roundness and Cylindricity (Ovality). Probably Taper in the bore. Poor surface finish. And Harmonics.

R
 

Martin W

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Thanks all
I am talking TIR at the tool tip.
Cheers
 
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atex57

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Say if you have a 2" bar with a cutting tool projecting .25" from the side it should cut a 2.5" diameter. If the runout near the tool is .010 then the tool will cut .010 larger than if the bar is perfectly straight. The tool is cutting from the theoretical centerline of the spindle bearings. The hole will be round to the capabilities of the setup. Just imagine a Criterion style boring head, it simply offsets from the centerline.

Ed.
 

Martin W

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Say if you have a 2" bar with a cutting tool projecting .25" from the side it should cut a 2.5" diameter. If the runout near the tool is .010 then the tool will cut .010 larger than if the bar is perfectly straight. The tool is cutting from the theoretical centerline of the spindle bearings. The hole will be round to the capabilities of the setup. Just imagine a Criterion style boring head, it simply offsets from the centerline.

Ed.
Thank you. Learned something new.
Cheers
Martin
 

eKretz

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The only thing you have to watch out for in this situation is if you are feeding the spindle out instead of feeding the table in while boring. If that runout changes during your cut, what do you suppose it will do to your bore size? Also, extending the spindle out much distance is likely to induce sag or even tilt in the head of the machine. If possible, always feed the table for boring, not the spindle.
 

eKretz

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Say if you have a 2" bar with a cutting tool projecting .25" from the side it should cut a 2.5" diameter. If the runout near the tool is .010 then the tool will cut .010 larger than if the bar is perfectly straight. The tool is cutting from the theoretical centerline of the spindle bearings. The hole will be round to the capabilities of the setup. Just imagine a Criterion style boring head, it simply offsets from the centerline.

Ed.
Just had another thought after rereading this. That is not necessarily true. The tool will not always cut the same amount larger as the bar is running out. If the tip of the tool is not inline with the max runout point it will cut a completely different size, depending on where it is in relation to that runout.

We'll use your 2" bar that's running out .010" with .25" tool tip projection as an example. If the max TIR point on the bar is at 0° in this case, and our tool tip is at 180°, the tool will cut a theoretical 2.490" bore. If it's at 0°, a theoretical 2.510" bore. Anywhere in between will produce a size within that range. At 90° or 270° it should hit 2.500" right on the money.

Anyway, after all that, I guess my point is: don't ever rely on tool stickout distance from a boring bar to set your boring tool unless it's for a roughing cut. Make your spot cut and set from there.

And yes, atex, I know you were also just using a theoretical example to explain your point, I was not saying that you don't already know this.
 

atex57

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I probably should have said "runout at the tool tip".

Any time I do HBM work or inplace lineboring it's trial cut and set the tool. Anything else will bite you. Your mention of feeding with the spindle is spot on, mine will cut smaller as I feed out. Feed the table and it cuts straight.

Ed.
 
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